Answer: The GREATEST number of bookmarks that Logan can make = 31.
Step-by-step explanation:
GIven: Total petals = 95
Number of petals required for each bookmark = 3
Number the number of bookmarks can be prepared from 95 petals = 95 ÷ (Petals required of each bookmark)
= 95÷3
![=31\dfrac{2}{3}\ \ \ \approx31\text{ [Round to the nearest whole number.]}](https://tex.z-dn.net/?f=%3D31%5Cdfrac%7B2%7D%7B3%7D%5C%20%5C%20%5C%20%5Capprox31%5Ctext%7B%20%20%20%20%5BRound%20to%20the%20nearest%20whole%20number.%5D%7D)
i.e. The GREATEST number of bookmarks that Logan can make = 31.
34255 = 5 * 13 * 17 * 31
203515 = 5 * 13 * 31 * 101
So GCD(34255, 203515) = 5 * 13 * 31 = 2015
Answer:
NPL
Step-by-step explanation:
The angles across from each other on a parallelogram are congruent
90/3 parts of silver = 30 times multiplied by
tin = 12 × 30 = 360g
lead = 8 × 30 = 240g
12.5 / 23 = 0.5434 parts per metal
tin = 12 × 0.5434 = 6.5kg
lead = 8 × 0.5434 = 4.5kg
silver = 3 × 0.5434 = 1.5kg
