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Genrish500 [490]
3 years ago
10

Find a a pair of numbers of both 4y-4x=48 and y= x-11

Mathematics
1 answer:
stich3 [128]3 years ago
4 0

Answer:

There is no solution because the slopes of the line are the same.

Step-by-step explanation:

4y - 4x = 48

    + 4x    + 4x        Add 4x to both sides

4y = 4x + 48          Divide both sides by 4

y = x + 12

Now set both equations equal to each other since they equal y

x + 12 = x - 11

-x         - x           Subtract x from both sides

12 ≠ -11                No Solution

If this answer is correct, please make me Brainliest!

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Please answer this question now
inn [45]

Answer:

t = 17.3

Step-by-step explanation:

The following data were obtained from the question:

Angle T = 87°

Opposite T = t =?

Opposite V = v = 14

Opposite U = u = 11

The value of t can be obtained by using cosine rule formula as shown below:

t² = v² + u² – 2vu CosT

t² = 14² + 11² – 2 × 14 × 11 × Cos87°

t² = 196 + 121 – 308 × Cos87°

t² = 317 – 16.119

t² = 300.881

Take the square root of both side

t = √300.881

t = 17.3

Therefore, the value of t is 17.3

6 0
3 years ago
An item is regularly priced at $70. Keiko bought it on sale for 80% off the regular price. How much did Keiko pay? $
pantera1 [17]

Answer:

$14

Step-by-step explanation:

80% of $70 is $14, saving him $56

8 0
2 years ago
Read 2 more answers
The mean salary if of 5 employees is $35900. the median is $37000. the mode is $382000. If the median payed employee gets a $310
mr Goodwill [35]

Answer:

Step-by-step explanation:

New median:40100

New mode:385100

5 0
3 years ago
Which equation represents the parabola shown on the
EastWind [94]

Answer:

y2=-8x is what's graphed so B.

Step-by-step explanation:

(I think you mistyped the choice)

3 0
3 years ago
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A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod
adell [148]

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0
3 years ago
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