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skelet666 [1.2K]
3 years ago
12

PLEASE HELP ME!!!!!!!!

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0

Option C: 64 \ cm^2 is the area of the composite figure.

Explanation:

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

b_1=10 \ cm

b_2=6 \ cm and

h=4 \ cm

Area of the trapezoid = \frac{1}{2} (b_1+b_2)h

Substituting the values, we get,

A=\frac{1}{2} (10+6)4

A=\frac{1}{2} (16)4

A=32 \ cm^2

Thus, the area of one trapezoid is $32 \ {cm}^{2}$

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2

Thus, the area of the composite figure is 64 \ cm^2

Hence, Option C is the correct answer.

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QUESTION 29
Shalnov [3]

The sum of the set of x - values given to us is calculated as; ∑X = -1

<h3>How to find the the sum of a set of data?</h3>

We are given;

X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6

1) ∑X = X1 + X2 + X3 + X4

∑X = 2 + (-8) + 4 + 1 = -1

2) ∑Y = Y1 + Y2 + Y3 + Y4

∑Y = 3 + (-8) + 10 + 6

∑Y = -11

3) ∑ X² = X₁² + X₂² + X₃² + X₄²

∑X² = (2)² + (-8)² + (4)² + (1)²

∑X² = 85

4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²

∑X² = (-3)² + (-8)² + (10)² + (6)²

∑X² = 209

Complete question is;

Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²

Read more about Sum of data at; brainly.com/question/15858152

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