Question

PLEASE HELP ME!!!!!!!!

Answer 1

Option C: $64 \ cm^2$ is the area of the composite figure.

Explanation:

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

$b_1=10 \ cm$

$b_2=6 \ cm$ and

$h=4 \ cm$

Area of the trapezoid = $\frac{1}{2} (b_1+b_2)h$

Substituting the values, we get,

$A=\frac{1}{2} (10+6)4$

$A=\frac{1}{2} (16)4$

$A=32 \ cm^2$

Thus, the area of one trapezoid is $32 \ {cm}^{2}$

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ $= 64 \ cm^2$

Thus, the area of the composite figure is $64 \ cm^2$

Hence, Option C is the correct answer.