15 1/3 - 6 1/4 - 4 2/3 = <span>4.41666666667 hours</span>
x is time and y is pencils that you have
'starts with 90' so at x=0, plot y=90
'gives away 15 every hour' so for every 1 hour, move 15 down on y
so at x=1, do 90-15=75 pencils
at x=2, do 75-15=60 pencils
etc
until you get to
x=6, do 15-15=0 pencils then stop because you can't give away 15 pencils when you have 0
see attachment for plot
I don't know how your segment tool works so you do it
if it draws a line, you only need 2 points, just do when x=0, y=90 and when x=6, y=0
try using the app Photomath for numbers 1-3!
<h3>
Answer:</h3>
25
<h3>
Step-by-step explanation:</h3>
Let w represent the weight of the animal in pounds, and d the age in days. The problem statement tells us ...
... w = 75 +2d
We want to find d when w > 125.
... 75 +2d > 125 . . . . . substitute the above expression for w
... 2d > 50 . . . . . . . . . subtract 75
... d > 25 . . . . . . . . . . . divide by 2
The animal will weigh more than 125 pounds when it is more than 25 days old.
Answer:
R-{13}
Step-by-step explanation:
We are given that
![f(x)=x+7](https://tex.z-dn.net/?f=f%28x%29%3Dx%2B7)
![g(x)=\frac{1}{x-13}](https://tex.z-dn.net/?f=g%28x%29%3D%5Cfrac%7B1%7D%7Bx-13%7D)
We have to find the domain of fog(x).
![fog(x)=f(g(x))](https://tex.z-dn.net/?f=fog%28x%29%3Df%28g%28x%29%29)
![fog(x)=f(\frac{1}{x-13})](https://tex.z-dn.net/?f=fog%28x%29%3Df%28%5Cfrac%7B1%7D%7Bx-13%7D%29)
![fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}](https://tex.z-dn.net/?f=fog%28x%29%3D%5Cfrac%7B1%7D%7Bx-13%7D%2B7%3D%5Cfrac%7B1%2B7x-91%7D%7Bx-13%7D%3D%5Cfrac%7B7x-90%7D%7Bx-13%7D)
Domain of f(x)=R
Because it is linear function.
Domain of g(x)=R-{13}
Because the g(x) is not defined at x=13
fog(x) is not defined at x=13
Therefore, domain of fog(x)=R-{13}