First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
If each of them got 1/3 of the deck then they would each get 7 cards
If T is the midpoint of SU, then ST ≅ TU.
Therefore we have the equation:
6x = 2x + 32 <em>subtract 2x from both sides</em>
4x = 32 <em>divide both sides by 4</em>
x = 8
ST = 6x → ST = 6(8) = 48
TU = ST, therefore ST = 48
SU = ST + TU = 2ST, therefore SU = 2(48) = 96
<h3>Answer: ST = 48, TU = 48, SU = 96</h3>
Answer:
1/9
Step-by-step explanation:
0.1(repeating)
Answer:
Yeah and i don't know how to answer that sorry
Step-by-step explanation:
you can't look it up some how?
