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11Alexandr11 [23.1K]

3 years ago

13

BRAINLIEST AND 5 STARS!!!!!!

1 answer:

lesantik [10]3 years ago

3 0

2/3 = 5/8 would be the one

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Help please i dont understand

kirza4 [7]

Vertical angles ate those that ate directly across from each other and share the same vertex. An example of this would be angles 5 and 7. These types of angles are also congruent, so angles 5 and 7 could be your congruent pair or another set of vertical angles like 1 and 3. A linear pair is two angles that together are a line. Basically, they are next ro each other (divided only by another vector) and are supplementary, adding up to 180 degrees. An example of this in the image is angles 1 and 2.

5 0

3 years ago

How is 2-2×6+3=-7?<br>The answer to this question

alekssr [168]

Answer:

PEMDAS

Step-by-step explanation:

Using PEMDAS or the order of operations, you first multiply 2 by 6

2-2×6+3

2-12+3

Then you can go in any order since addition and subtraction take the same precedence.

-10+3=-7

5 0

3 years ago

Graph the line with slope 4 and y-intercept -9

Monica [59]

go down to (0, -9) on the graph, from there go up four and over one and plot the next point, up four over one again, and repeat

7 0

3 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago

Ayudenmeee por favor

Dmitry [639]

B because I’m just guessing

8 0

3 years ago