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andre [41]
4 years ago
13

A flare is fired from 4 feet above the ground at a speed of 64 feet per second. The flare will fall to the ground after it burns

out.

Mathematics
1 answer:
gavmur [86]4 years ago
7 0

Answer:

<h2>68 feet.</h2>

Step-by-step explanation:

At maximum height, the velocity of the flare will be zero.

If the flare height above the ground is modeled by the equation

h = -16t²+64t+4

Velocity = dh/dt = 0

-32t + 64 = 0

-32t = -64

t = -64/-32

t = 2secs

This shows that the flare reaches its maximum height after 2secs.

To get the maximum height of the flare, we will substitute t = 2s into the equation h = -16t²+64t+4

h = -16(2)² + 64(2)+4

h = -64+128+4

h = 64+4

h = 68 feet

The maximum height of the flare is 64 feet.

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A local citizen wants to fence a rectangular community gardenn. The length of the garden should be at least 110ft,and the distan
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A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutions

let
x---------------> t<span>he length of the garden
</span>y---------------> the wide of the garden

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x>=110
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Part A) <span>Write a system of inequality that model the possible dimensions of he garden
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x>=110
x+y <= 190


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using a graph tool
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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

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