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xenn [34]
3 years ago
7

What is the length of the unknown leg in the right triangle 9 and square root of 113

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Can you try rewording this question?

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Describe a process you would use to create the perpendicular bisector to a segment AB using only an unmarked straightedge and an
Murrr4er [49]

You'll have to c<span>ompass tip on A and draw a small ark with pencil approximately in the middle above AB line, now compass tip to point B and cross the ark you made previously.
Do the same on the opposite side without making any change to the compass 
Join the lines where crosses of arks on the both side meet and then ,it's done.</span>
8 0
2 years ago
What happens to a figure in a reflection
zepelin [54]
So to answer this question all you need is the definition of a reflection
A reflection in my explanation is a flip of the figure to be on the opposite side NOT changing the shape but only flipping the coordinates
4 0
3 years ago
The diameter of a semicircle is 8 miles. What is the semicircle's perimeter? Use 3.14 for ​.
wlad13 [49]

Answer:

41.13 cm

Step-by-step explanation:

ITSSSS RIGHTTTTTTTTT

7 0
2 years ago
Read 2 more answers
???? Help plz ?…. It’s a grade
Aleks [24]

Answer:

Yes it does show a dilation

4 0
2 years ago
If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.​
larisa86 [58]

Answer:

The answer is

<h2>2√74 or 17.20 units</h2>

Step-by-step explanation:

The length of w line segment between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(-8, 7) and T (6,-3)

The length of ST is

|ST|  =  \sqrt{ ({ - 8 - 6})^{2} +  ({7 + 3})^{2}  }  \\  =  \sqrt{ ({ - 14})^{2} +  {10}^{2}  }  \\  =  \sqrt{196 + 10}  \\  =  \sqrt{296}  \\  = 2 \sqrt{74}  \\  = 17.2046505...

We have the final answer as

<h3>2√74 or 17.20 units</h3>

Hope this helps you

8 0
3 years ago
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