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beks73 [17]
3 years ago
12

How do you solve for the slope of a line with the equation ax^2 + bx + c?

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
<h2>The graph of y = ax^2 + bx + c </h2><h2>A nonlinear function that can be written on the standard form </h2><h2>ax2+bx+c,where a≠0 </h2><h2>All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is </h2><h2> y=x2 </h2><h2> The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate </h2><h2>x=−b2a </h2><h2>The y-coordinate of the vertex is the maximum or minimum value of the function. </h2><h2>a > 0                   parabola opens up                    minimum value </h2><h2>a < 0                    parabola opens down              maximum value </h2><h2> A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression. </h2><h2>The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation </h2><h2>x=−b2a </h2><h2>The y-intercept of the equation is c. </h2><h2> When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.</h2>
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