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beks73 [17]
3 years ago
12

How do you solve for the slope of a line with the equation ax^2 + bx + c?

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
<h2>The graph of y = ax^2 + bx + c </h2><h2>A nonlinear function that can be written on the standard form </h2><h2>ax2+bx+c,where a≠0 </h2><h2>All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is </h2><h2> y=x2 </h2><h2> The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate </h2><h2>x=−b2a </h2><h2>The y-coordinate of the vertex is the maximum or minimum value of the function. </h2><h2>a > 0                   parabola opens up                    minimum value </h2><h2>a < 0                    parabola opens down              maximum value </h2><h2> A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression. </h2><h2>The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation </h2><h2>x=−b2a </h2><h2>The y-intercept of the equation is c. </h2><h2> When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.</h2>
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3 years ago
URGENT HELP PLEASE
sammy [17]

Answer:

slope1 : 7,  slope 2 = 3     solution: (2,5)

Step-by-step explanation:

I simplify some steps

pair 1:    x1   0     2

            y1   -9     5 ........ -9, y1 intercept

pair 2:   x2   0    2

             y2  -1    5   ........ -1, y2 interept

2 pairs meet at (2,5)

y=7x-9 ......A

y=3x-1  ......B

A-B    0=4x-8

4x=8

x=2

y=5

slope 1=( y2-y1) / (x2-x1) = (5- -9)/(2-0) = 14/2 =7

slope 2 = (5 - -1) / (2 - 0) = 6/2 = 3

8 0
3 years ago
6h − (9−3h) = 6 − 3 (h+2) <br><br> h=3/2 <br><br> h=3/4 <br><br> h=17/6 <br><br> h=7/2
Andre45 [30]
I would try going with h =7/2 if that is wrong just rate me 1
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Write an equation of the line through the given points<br><br>(0, -2), (3, -2)<br>​
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Y= my+b
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If w varies inversely with the square root of t and w = 5 when t = 49,
VARVARA [1.3K]

Answer:

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