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boyakko [2]
3 years ago
15

The weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that ca

n be set by the operator. At what level should the mean weight be set if it required that only 1% of the bags weigh less than 10.5 kilograms? Round the answer to 2 decimal places.
Mathematics
1 answer:
Sloan [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that the  weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator.

Let the mean be M.

Only 1% of the bags weigh less than 10.5 kilograms

i.e. P(X<10.5) = 0.01

corresponding Z value for P(Z<z) = 0.01 is -0.025

i.e. 10.5 = M-0.025(0.055)

Solve for M from the above equation

M = 10.5+0.025(0.055)\\=10.501375

Rounding off we get

10.50 kgs

Mean weight should be fixed as 10.50 kg.

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Sergio039 [100]

Answer:

12.5

Step-by-step explanation:

Step 1:

0.4 ( 3b + 10 ) = 19     Equation

Step 2:

1.2b + 4 = 19       Multiply

Step 3:

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Step 4:

15 ÷ 1.2    Divide

Answer:

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Hope This Helps :)

7 0
3 years ago
The product of twice a number and six is the same as the difference of eleven times the number and 6/5 . Find the number
Rom4ik [11]

Answer:

-6/5

Step-by-step explanation:

solution;

let,the number be x,

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3 0
3 years ago
Major help ASAP!
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Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).

Center of center of dilation is (2,-2).

Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.

Now, we need to apply rule for dilation with the scale factor 5/3.

Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.

We will extend RS to 5 units and TS also 5 units.

The new resulting image would be dilated triangle by a scale factor 5/3.


4 0
3 years ago
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