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boyakko [2]
3 years ago
15

The weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that ca

n be set by the operator. At what level should the mean weight be set if it required that only 1% of the bags weigh less than 10.5 kilograms? Round the answer to 2 decimal places.
Mathematics
1 answer:
Sloan [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that the  weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator.

Let the mean be M.

Only 1% of the bags weigh less than 10.5 kilograms

i.e. P(X<10.5) = 0.01

corresponding Z value for P(Z<z) = 0.01 is -0.025

i.e. 10.5 = M-0.025(0.055)

Solve for M from the above equation

M = 10.5+0.025(0.055)\\=10.501375

Rounding off we get

10.50 kgs

Mean weight should be fixed as 10.50 kg.

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john scored 15 points his first game. In his last game he scored 20 points. What was his percent of increase?
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\huge\mathrm{ \it{Answer࿐}}

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2 years ago
Tom caught 4 fish and his son caught 12 fish. The number of fish that Tom’s caught was what percent of the number of fish his so
Fofino [41]

Answer:

33.3 % (Approx) percent of fish that Tom’s caught  of the number of fish his son caught .

25% is the percent of the total amount Tom caught.

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ values}

Part First

As given

Tom caught 4 fish and his son caught 12 fish.

Here

Part value = 4

Total value = 12

Put in the formula

Percentage = \frac{4\times 100}{12}

Percentage = \frac{400}{12}

Percentage = 33.3 % (Approx)

Therefore the 33.3 % (Approx) percent of fish that Tom’s caught  of the number of fish his son caught .

Second Part

As given

Tom caught 4 fish and his son caught 12 fish.

Total number of fish caught = 4 + 12

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Put in the formula

Percentage = \frac{4\times 100}{16}

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Percentage = 25%

Therefore the 25% is the percent of the total amount Tom caught.



8 0
3 years ago
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