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irakobra [83]
3 years ago
8

PLEASE HELP ILL MAKE YOU BRAINLIEST!!!!What is the length of line segment MQ?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
The length is 11 units. x3
Marat540 [252]3 years ago
6 0

Answer:C

Step-by-step explanation:

11 units

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Will mark brainliest!
kvasek [131]

Answer:

B

Step-by-step explanation:

To find f(- 2) substitute x = - 2 into f(x)

f(- 2) = - 2(- 2)³ + (- 2)² + 4(- 2) - 3

        = - 2(- 8) + 4 - 8 - 3

        = 16 + 4 - 8 - 3

        = 9 → B

6 0
3 years ago
Read 2 more answers
20194+9283 - 372 = ? <br><br>will give brainliest or whatever ‍
klemol [59]

20,194+9,283 - 372 = 29,105

6 0
3 years ago
13. Calcule:
8090 [49]
Your answer will be B.
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B4%7D%28%20%5Csqrt%7B8%7D%20%2B%203%20%29" id="TexFormula1" title="\sqrt{4}( \sqrt{8}
AfilCa [17]

Answer: 11.65685....

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
Allisa [31]

Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0
3 years ago
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