Answer:
Ok, so we can express the boys as another letter. just express them as the letter B for boys.
Step-by-step explanation:
I really don't know why.
Answer:
8 3/
4
Step-by-step explanation:
3 1/
2
×
2 1
/2
=
7 × 5
2 × 2
=
35
/4
=
8 3
/4
The annual income tax paid by the person is: $4,500.
<h3>Annual income tax</h3>
Using this formula
Annual income tax=[Salary÷(1-percentage deduction)]- Salary
Let plug in the formula
Annual income tax=[40,500÷(1-10%)]-40,500
Annual income tax=45,000-40,500
Annual income tax=4500
Therefore the annual income tax paid by the person is: $4,500.
Learn more about annual income tax here:brainly.com/question/26316390
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Answer:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Step-by-step explanation:
Let's define the events:
L: The student is proficient in reading
M: The student is proficient in math
The probabilities are given by:
![P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64](https://tex.z-dn.net/?f=P%20%28L%29%20%3D%200.81%5C%5CP%20%28M%29%20%3D%200.74%5C%5CP%20%28L%5Cbigcap%20M%29%20%3D%200.64)
![P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17](https://tex.z-dn.net/?f=P%20%28M%5Cbigcap%20L%5Ec%29%20%3D%20P%20%28M%29%20-%20P%20%28M%5Cbigcap%20L%29%20%3D%200.74%20-%200.64%20%3D%200.1%5C%5CP%20%28M%5Ec%5Cbigcap%20L%29%20%3D%20P%20%28L%29%20-%20P%20%28M%5Cbigcap%20L%29%20%3D%200.81%20-%200.64%20%3D%200.17)
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Area of the rectangle is 2*6=12 in^2
12 could be = 1*12 or 2*6 or 3*4
P could be 2*(1+12)=2*13=26
2*(2+6)=2*8=16
2*(3+4)=2*7=14
the answer is 24 in (c)