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mash [69]
3 years ago
9

Ram has 35 gel pens.. please help this is for kahn academy

Mathematics
1 answer:
disa [49]3 years ago
5 0

Answer:

After the 35 gel pens??

Step-by-step explanation:

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Which expression fits this description?
Gemiola [76]

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i didthe math, its c

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3 years ago
What is the length of a piece of cloth that is 5 centimeters wide an area of 20 cm^2?
natima [27]

4 centimeters is the length

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3 years ago
Which representation shows a nonproportional relationship between x and y? 6 4 2 1 FA 11 3 y = -X -9-8-7-6-5-4-3-2-1 334 5 6 7 8
aleksandr82 [10.1K]

proportional relationships have constant ratios.

the graph is a line, so it is a proportional relationship. (A)

the function is in the form y=kx (proportional function) (C)

Find the ratio of the tables: (B)

m=\frac{-0.8-(-1.6)}{-2-(-4)}=0.4=\frac{0.4-(-0.8)}{1-(-2)}=\frac{1.2-0.4}{3-1}=

D

m=\frac{-0.2-(-1)}{-3-(-5)}=0.4=\frac{1.8-(-0.2)}{2-(-3)}=\frac{3-1.8}{5-2}

All represent a proportional relationship

4 0
1 year ago
The diagram shows two nested triangles that share a vertex.Find a center and a scale factor for a dilation that would move the l
nasty-shy [4]

Transformation that changes the size of a shape is referred to as dilation.

  • The scale factor that moves the large triangle to the small one is 1/5
  • The center of dilation is: (-1,1)

<u>The center of dilation</u>

From the diagram (see attachment), the triangles share a common vertex at (-1,1)

This means that, the center of dilation is (-1,1)

<u>The scale factor of dilation</u>

To do this, we divide the side length of the small triangle with the corresponding side of the large triangle.

From the attached image:

\mathbf{Base\ of\ small\ triangle = 1}

\mathbf{Base\ of\ large\ triangle = 5}

So, the scale factor (k) from large to small is:

\mathbf{k = \frac{Base\ of\ small\ triangle}{Base\ of\ large\ triangle} }

\mathbf{k = \frac{1}{5} }

Read more about dilation at:

brainly.com/question/13176891

3 0
3 years ago
Identify the conic whose equation is given.
irina1246 [14]

Answer:

Hyperbola  

Step-by-step explanation:

The polar equation of a conic section with directrix ± d  has the standard form:

r=ed/(1 ± ecosθ)

where e = the eccentricity.

The eccentricity determines the type of conic section:

e = 0       ⇒ circle

0 < e < 1  ⇒ ellipse

e = 1        ⇒ parabola

e > 1        ⇒ hyperbola

Step 1. <em>Convert the equation to standard form </em>

r = 4/(2 – 4 cosθ)

Divide numerator and denominator by 2

r = 2/(1 - 2cosθ)

Step 2. <em>Identify the conic </em>

e = 2, so the conic is a hyperbola.

The polar plot of the function (below) confirms that the conic is a hyperbola.

5 0
4 years ago
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