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3 years ago

Solve this proportion. 8/x=2/5 x=

1 answer:

5 0

8/x = 2/5
cross multiply
(2)(x) = (8)(5)
2x = 40
x = 40/2
x = 20

now check out ur fractions : 8/20 = 2/5....notice that they are equivalent fractions...just like proportions...nothing but equivalent fractions

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How do I do this delta math question?

KonstantinChe [14]

It does not represent a polynomial

7 0

3 years ago

The amount of soft drink in a bottle is a Normal random variable. Suppose that in 7% of the bottles containing this soft drink t

WITCHER [35]

Answer:

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

7% of the bottles containing this soft drink there are less than 15.5 ounces

This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.

$Z = \frac{X - \mu}{\sigma}$

$-1.475 = \frac{15.5 - \mu}{\sigma}$

$15.5 - \mu = -1.475\sigma$

$\mu = 15.5 + 1.475\sigma$

10% of them there are more than 16.3 ounces.

This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{16.3 - \mu}{\sigma}$

$16.3 - \mu = 1.28\sigma$

$\mu = 16.3 – 1.28\sigma$

From above

$\mu = 15.5 + 1.475\sigma$

$15.5 + 1.475\sigma = 16.3 – 1.28\sigma$

$2.755\sigma = 0.8$

$\sigma = \frac{0.8}{2.755}$

$\sigma = 0.29$

The mean is

$\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93$

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

6 0

3 years ago

.Here is a 90% confidence interval estimate of theproportion of adults who say that thelaw goes easy on celebrities: 0.645

bulgar [2K]

Answer:

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

In this question:

CI is between 0.645 and 0.842. So the best estimate of the proportion is:

(0.645+0.842)/2 = 0.7435

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

5 0

3 years ago

High school students from grades 9–10 and 11–12 were asked to choose the kind of band to have play at a school dance: rap, rock,

yanalaym [24]

The correct two-way frequency table for the date will look like this:

RAP ROCK COUNTRY TOTAL
Grades 9-10 40 30 55 125
Grades 11-12 60 25 35 120
TOTAL 100 55 90 245

The sum of the row total is equal to the sum of the column total
125 + 120 = 100 + 55 + 90
245 = 245

8 0

3 years ago

Read 2 more answers

PLEASE HELP! ! ! urgent!

sertanlavr [38]

Answer:

$6(\frac{1}{3} \times\frac{7}{5} )=(6\times\frac{1}{3} )\frac{7}{5}$

$Answer: B$

Hope it helps...

Have a great day!!

8 0

3 years ago