Answer:
C = 288 kg
Step-by-step explanation:
Given:
C = 72m^2/4
where,
C = approximate number of calories
m = animal mass in kilograms.
Find C when m = 16
C = 72m^2/4
= 72 * (16)^2/4
= 72 * (16)^1/2
= 72 * √16
= 72 * 4
= 288
C = 288 kg
Answer:
100(a divided by b)
this is because for example, 1/2
100(1 divided by 2)
100(0.5)
50
50%
Answer:
y = -6 + 1.2*x is the answer I would use, but see the note below.
Step-by-step explanation:
Let x = the number of minutes.
Let y = the temperature at any given time.
y = -6 + 1.2*x
This is the equation that you would use if you were calculating y with a calculator. If you are in a chemistry class it should be written as
y = - 6°C + 1.2°x/ min
Compare fractions<span> using a </span>benchmark fraction<span>. Compare two </span>fractions<span> with different numerators and different denominators, e.g., by creating common denominators or numerators, or by comparing to a </span>benchmark fraction<span> such as 1/2. Recognize that comparisons are valid only when the two </span>fractions<span> refer to the same whole.</span>
Answer:
null hypothesis is p=0.41
alternate hypothesis is p<0.41
Sample proportion is 0.36
critical value for a = 0.01 is -2.2326
z-statistic is −1,0166
critical value for the level of significance 0.10 is -1.28155
we fail to reject the null hypothesis in 0.01 significance level.
Step-by-step explanation:
Let p be the proportion of the viewing audience of 11:00PM CBS newscast in the area. Then
: p=0.41
: p<0.41
Sample proportion is 0.36 and critical value (left tailed) for a=0.01 is -2.2326
sample proportion Z-score can be calculated as follows:
z(0.36)=
where
- p(s) is the sample proportion of vieved newscast (0.36)
- p is the proportion assumed under null hypothesis. (0.41)
- N is the sample size (100)
putting the numbers z(0.36)=
=−1,0166
if the level of significance is 0.10 then critical value would be -1.28155.
in 0.01 significance level sample mean is not in the critical region, therefore we fail to reject the null hypothesis.