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3 years ago

PLEASE HELP ME!! THANKS!! BRAINLIEST IF CORRECT!

Mathematics

2 answers:

-BARSIC- [3]3 years ago

7 0

Answer:

The answer is +2

Step-by-step explanation:

b is the answer

Murrr4er [49]3 years ago

4 0

When the calcium atom loses electrons, it's charge increases by the number of electrons lost.

It loses 2 electrons, so it's charge increases by 2.

The answer is +2

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Convert the time. Enter your answer in the box.<br><br> 4 minutes 53 seconds = <br> seconds

ch4aika [34]

Answer:

293 seconds

Step-by-step explanation:

60*4=240

240+53=293

3 0

2 years ago

The base of the right prism is a rhombus with the side 7 cm. The altitude of the prism is h=13 cm. Find the lateral area of the

Art [367]

Answer:The lateral area is $364\ cm^{2}$

Step-by-step explanation:

we know that

The lateral area of the right prism is equal to

$LA=Ph$

where

P is the perimeter of the base

H is the height of the prism

Find the perimeter of the base P

$P=4(7)=28\ cm$ ----> the rhombus has four equal sides

$h=13\ cm$

substitute

$LA=28(13)=364\ cm^{2}$

6 0

3 years ago

Read 2 more answers

A chemist recorded the change in temperature of a cooling liquid as −25.5°F−25.5°F over a 1.5 minute period. The temperature fel

Natasha2012 [34]

2 is the answer okay

7 0

3 years ago

Read 2 more answers

FIRST TO ANSWER GETS BRAINLIEST!

scZoUnD [109]

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

circle
PEMDAS

<h3>tips and formulas:</h3>

$\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$