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lawyer [7]
3 years ago
14

Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation

are unknown. The first sample has 25 data values. The second sample has 64 data values. Then we construct a 95% confidence interval for each sample to estimate the population mean. Which confidence interval will have greater precision (smaller width) for estimating the population mean?
Mathematics
1 answer:
Leto [7]3 years ago
3 0

Answer:

The 95% confidence interval obtained with a sample size of 64 will give greater precision.            

Step-by-step explanation:

We are given the following in the question:

A 95% confidence interval is calculated with the following sample sizes

n_1 = 25\\n_2 = 64

The population mean and standard deviation are unknown.

Effect of sample size on confidence interval:

  • As the sample size increases the margin of error decreases.
  • As the margin of error decreases the width of the confidence level decreases.
  • Thus, with increased sample size the width of confidence level decreases.

If we want a confidence interval with greater precision that is smaller width, we have to choose the higher sample size.

Thus, the 95% confidence interval obtained with a sample size of 64 will give greater precision.

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Matthew has 2 dozen eggs. He uses 3/4 of the first dozen and 5/6 of the second dozen for baking.
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What is the solution to the following system of equations 4x + 2 = -2y 6y - 18 = 6x
Pavel [41]

Answer:

The solution to the system of equations are;

x = -4/3

y = 5/3

Step-by-step explanation:

To find the Solution, we would carry the Operation simultaneously.

4x + 2 = -2y .........(i)

6y - 18 = 6x ..........(ii)

First let's rearrange the equations, to make the journey smoother

2y + 4x = -2 ...........(iii)

6y - 6x = 18 ...........(iv)

Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.

3.2y + 3.4x = -2 . 3

6y + 12x = -6............... (v)

Let's subtract equation (v) from equation (iv)

= 0y - 18x = 24

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x = - 24 / 18

x = -4/3

Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:

6y - 18 = 6x

6y - 18 = 6 (-4/3)

6y - 18 = -8

6y = -8 + 18

6y = 10.

y = 10 / 6

y = 5/3

The solution to the system of equations are;

x = -4/3

y = 5/3

8 0
3 years ago
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