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zysi [14]
4 years ago
10

Which compound inequality has no solution? –2 < x and 2x + 6 < 14 4 < x and 6x – 11 < 14 10 < x and 2x – 3 < 1

4 14 < x and 0.5x + 6 < 14
Mathematics
2 answers:
Maslowich4 years ago
7 0
The correct answer is 10< X AND 2X-3< 14
Sonbull [250]4 years ago
3 0

Answer:

10 < x and 2x – 3 < 14

Step-by-step explanation:

Got it right

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(3.1)(0.02)<br> math help
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Answer:

0.062

Step-by-step explanation:

(3.1)(0.02)=0.062

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3 years ago
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BRAINLIESTTT ASAP! PLEASE HELP ME :)
kumpel [21]

The correct answers are B and D.

A is false because, even though it's true that 4 points are not necessarily on the same line, it is not required that they are collinear in order for them to be coplanar.

B is true: two points always lie on the same line (and thus also in infinite same planes), but four points are not always coplanar

C is false. As a counterexample pick the four points (0,0, 0), (1, 0, 0), (0, 1, 0), (0, 0, 1).

D is true: two points are always on the same line, three points always lie in a common plane, but 4 points are not necessarily coplanar.

8 0
3 years ago
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denis23 [38]
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4 0
3 years ago
What us the value of the discriminant of the quadratic equation -2^2=-8x+8 and what does its value mean about the number of a re
svlad2 [7]

ANSWER

The discriminant is zero.

The given equation has one real root.

EXPLANATION

The given quadratic equation is:

- 2 {x}^{2}  =  - 8x + 8

We rewrite this in the form;

a {x}^{2}  + bx + c = 0

- 2 {x}^{2}  + 8x  - 8 = 0

This means that,

a=-2, b= 8, c=-8

The discriminant is given by;

D=b² - 4ac

That is:

D =  {8}^{2}  - 4( - 2)( - 8)

D =  64  - 64 = 0

Therefore the discriminant is zero.

This tells us that the quadratic equation has one real root.

In order words, the given quadratic equation has a repeated real root.

3 0
4 years ago
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