Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer:oh okay
Step-by-step explanation:
Answer:
x = 15.7945
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sinθ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Angle θ = 33°
Opposite Leg = <em>x</em>
Hypotenuse = 29
<u>Step 2: Find Angle</u>
- Substitute in variables [sine]: sin33° = x/29
- [Multiplication Property of Equality] Multiply 29 on both sides: 29sin33° = x
- Rewrite: x = 29sin33°
- Evaluate: x = 15.7945
Answer:
Saturday=403 tickets
Step-by-step explanation:
1246-314-529=403
hello :)
so here i am assuming that 66m^2 is the area and the height is 6.3 (sorry, but the way you wrote it is a bit funny, its all good tho)
so to calculate area it is hieght multipled by width
so you have to divide 66 by 6.3, which gives you this very long number : 10.4761904762
i would personally round it to either just 10 or 10.5
so you would want to write the answer as ≈10.5
hope that helped!
i would appreciate it if you voted me as brainliest :)
