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3 years ago

Calculate the distance between the two given point T(6,-2),U(-2,-12)

1 answer:

3 0

Use the distance formula: $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

(6, -2), (-2, -12)
$\sqrt{(-2 - 6)^2 + (-12 - -2)^2}$ ⇒ $\sqrt{(-8)^2 + (-10)^2}$
$\sqrt{64 + 100}$ ⇒ $\sqrt{164}$
$\sqrt{164}$ = 12.8

The distance between points T and U is 12.8 units.

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Natasha_Volkova [10]

Answer:

B. The graph flips over the x-axis

Step-by-step explanation:

<u>Properties of : c · f(x)</u>

- Graph opens wider/more narrow

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- If the absolute value of c is less than one, it widens

- It can also affect any applied horizontal/vertical shifts

- If c is negative, the shape is reflected over the x-axis (upside-down)

<em><u>In this case, the question is only asking if the function flips a certain way. As seen, "c," (as shown above) is -1, which is less than one. This means that the function will be flipped over the x-axis.</u></em>

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3 years ago

20+(5 + 7) = x - 14 I need help take your time

adelina 88 [10]

Answer: x = 46

Step-by-step explanation: 20 + (5 + 7) = x - 14, 20 + (12) = x - 14

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3 years ago

Read 2 more answers

I am a regular polygon. Each of my exterior angles has a measure of 6 and 2/3 degrees. How many sides do I have?

Alik [6]

A polygon is a triangle it has 3 sides.

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3 years ago

Clarke borrows 16000 to buy a car. He pays simple interest at an annual rate of 6% over a period of 3.5 years . How much does he

Basile [38]

The answer is $19,360 because we multiply the annual interest rate of 6% or .06 by 3.5 years and we get a total interest of .21. The answer is found by performing $16,000 times 1.21 and we get $19,360.

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4 years ago

Explain how to find the vertex of 2x^2+12x+16

Elina [12.6K]

The vertex form:

$y=a(x-h)^2+k\\\\(h,\ k)-vertex$

Use $(a+b)^2=a^2+2ab+b^2\qquad(*)$

$2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2$

<h3>Answer: (-3, -2).</h3>

Other method:

$f(x)=ax^2+bx+c\\\\vertex:(h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)$

We have

$f(x)=2x^2+12x+16\\\\a=2,\ b=12,\ c=16$

Substitute:

$h=\dfrac{-12}{(2)(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+16=2(9)-36+16=18-36+16=-2$

<h3>Answer: (-3, -2).</h3>

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4 years ago