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asambeis [7]
3 years ago
11

Calculate the distance between the two given point T(6,-2),U(-2,-12)

Mathematics
1 answer:
slava [35]3 years ago
3 0
Use the distance formula: \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

(6, -2), (-2, -12)
\sqrt{(-2 - 6)^2 + (-12 - -2)^2} ⇒ \sqrt{(-8)^2 + (-10)^2}
\sqrt{64 + 100} ⇒ \sqrt{164}
\sqrt{164} = 12.8

The distance between points T and U is 12.8 units.
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4. Simplify the following.<br>3<br>a. 2-X5-:11<br>3<br>x5<br>5<br>6<br>7​
Ulleksa [173]

Answer:

<h2>1 \frac{1}{4}</h2>

Step-by-step explanation:

2 \frac{3}{7}  \times  5\frac{5}{6}   \div 11 \frac{1}{3}

Convert the mixed number to an improper fraction

\frac{17}{7}  \times  \frac{35}{6}  \div  \frac{34}{3}

To divide by a fraction, multiply the reciprocal of that fraction

\frac{17}{7} \times  \frac{35}{6}  \times  \frac{3}{34}

Reduce the number with the G.C.F 7

17 \times  \frac{5}{6}  \times  \frac{3}{34}

Reduce the numbers with the G.C.F 17

\frac{5}{6}  \times  \frac{3}{2}

Reduce the numbers with the G.C.F 3

\frac{5}{2}  \times  \frac{1}{2}

Multiply the fraction

\frac{5}{4}

In mixed fraction:

1 \frac{1}{4}

Hope this helps..

Good luck on your assignment...

4 0
3 years ago
Solve the system of equations. Show your work.<br> y = x^2 -3x +4 <br> x + y = 4
sesenic [268]

Answer:

x + y = 2 ,  y = x 2 − 4 x + 4

Replace all occurrences of  

y

with  x 2 − 4 x + 4

in each equation.

x 2 − 3 x + 4 = 2 y = x 2 − 4 x + 4

Solve for  

x

in the first equation.

x = 2 , 1 y = x 2 − 4 x+ 4

Replace all occurrences of  

x  with  2

in each equation.

y=0 x = 2

Replace all occurrences of  x

with  1

in each equation.

y = 1 x = 1

The solution to the system is the complete set of ordered pairs that are valid solutions.

( 2 , 0 ) ( 1 , 1 )

The result can be shown in multiple forms.

Point Form:

( 2 , 0 ) , ( 1 , 1 )

Equation Form:

x=2 , y = 0 x = 1 , y = 1

Step-by-step explanation:

3 0
3 years ago
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