1. Three people went to lunch at a buffet restaurant that charges $9.99 per

The equilateral triangle and the rectangle have the same perimeters. Find the value of x.

castortr0y [4]

We can't answer the question, you haven't given us the information, we need to know what the x is here, or if they gave you a value.

3 0

3 years ago

At CD Shack, all used CDs are the same price. Jesse spent $54 and Mimi spent $66 on used CDs. What is the most each used CD coul

Alinara [238K]

Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.

The grew greatest price that is in both lists is $6.

How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.

Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
___________________
Hope this helps you

5 0

3 years ago

A person has eaten 2/5 of a cake. When his family comes he wants to split it even with 10 people. How much of the cake will each

sergij07 [2.7K]

Each person will get 3/5 of the cake

6 0

3 years ago

Read 2 more answers

A sales manager wanted to determine if increasing sales commissions by 5% would increase employee satisfaction. Her analyst dete

Dafna11 [192]

Answer:

c. We have evidence that there is a difference in population median employee satisfaction rating before and after the commission change.

Step-by-step explanation:

Pvalue is less than the alpha-level:

If the pvalue is less than the alpha-level, we have that there is sufficient evidence of the hypothesis for the population mean/median/standard deviation we are testing.

In this question:

Pvalue less than the alpha-level, so there is evidence that there is a difference in the population median. This means that the correct answer is given by option C.

4 0

3 years ago

Estimate the minimum and maximum ages for typical textbooks currently used in college courses, then use the range rule of thumb

Maksim231197 [3]

Answer:

$n=(\frac{1.64(4)}{0.25})^2 =688.537 \approx 689$

So the answer for this case would be n=689 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: "Suppose that the minimum and maximum ages for typical textbooks currently used in college courses are 0 and 8 years. Use the range rule of thumb to estimate the standard deviation.

Estimate the minimum and maximum ages for typical textbooks currently used in college courses, then use the range rule of thumb to estimate the standard deviation. Next, find the size of the sample required to estimate the mean age (in years) of textbooks currently used in college courses. Use a 90% confidence level and assume that the sample mean will be in error by no more than 0.25 year."

Solution for the problem

First we need ti find the estimation for the standard deviation using the Rule of thumb, with the following formula:

$s \approx \frac{R}{4}$

Where R is the range defined as :

$R = Max - Min = 8-0 = 8$

So then the deviation would be approximately:

$s \approx 4$

Important concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error (ME) is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

And on this case we have that $ME =\pm 0.25$ and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (2)

We can assume that the estimator for the population deviation from the rule of thumb is $\hat \sigma = s= 4$

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got $z_{\alpha/2}=1.64$ , replacing into formula (2) we got:

$n=(\frac{1.64(4)}{0.25})^2 =688.537 \approx 689$

So the answer for this case would be n=689 rounded up to the nearest integer

6 0

3 years ago