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andriy [413]
3 years ago
12

Simplify using order of operation 18+4×3

Mathematics
2 answers:
Mrac [35]3 years ago
5 0

The order of operation is divided in 4 options:

1st - Breaking dow parenthesis

2nd - Square roots / exponents

3rd - Multiplication / division

4th - Addition / Subtraction


So in your case the expression will look like this:

18 + 4 * 3 =  → we solve the multiplication first

18 + 12 =  → secondly we solve the addition (this is the simplified operation)

30 → final answer


Hope it helped,


BioTeacher101

irga5000 [103]3 years ago
3 0

Here is the equation:

18+4 \times 3

You have to use PEMDAS

\bf Parentheses \\ Exponents \\ Multiplication\\ Division \\ Addition \\ Subtraction

Since multiplication is before addition, first multiply. You need to multiply 4 by 3.

4 \times 3 = 12

Here is your new equation:

18+12

All you need to do is add the two numbers. Add:

18+12=30

That means your answer is 30

<em>If you have any questions, feel free to ask in the comments! :)</em>

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If i^2 = −1 and x = i + 9, which is the result of squaring x?
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Answer:

80 + 18i

Step-by-step explanation:

i² = -1

x = i + 9

x² = (i + 9)²

Applying; (a + b)² = a² + 2ab + b² concept,

x² = i² + 18i + 81

We know that i² = -1

So x² = -1 + 18i + 81

x² = 81 - 1 + 18i = 80 + 18i

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What is the solution set of the inequality x5 + x4 - 6x3 + x2 + x - 6 ≥ 0?
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6 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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