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3 years ago

Simplify using order of operation 18+4×3

Mathematics

2 answers:

Mrac [35]3 years ago

5 0

The order of operation is divided in 4 options:

1st - Breaking dow parenthesis

2nd - Square roots / exponents

3rd - Multiplication / division

4th - Addition / Subtraction

So in your case the expression will look like this:

18 + 4 * 3 = → we solve the multiplication first

18 + 12 = → secondly we solve the addition (this is the simplified operation)

30 → final answer

Hope it helped,

BioTeacher101

irga5000 [103]3 years ago

3 0

Here is the equation:

$18+4 \times 3$

You have to use PEMDAS

$\bf Parentheses \\ Exponents \\ Multiplication\\ Division \\ Addition \\ Subtraction$

Since multiplication is before addition, first multiply. You need to multiply 4 by 3.

$4 \times 3 = 12$

Here is your new equation:

$18+12$

All you need to do is add the two numbers. Add:

$18+12=30$

That means your answer is 30

<em>If you have any questions, feel free to ask in the comments! :)</em>

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Greeley [361]

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

$2^x=1-3^x$

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

$2^{-0.75}=1-3^{-0.75}$

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

$2^{-1.25}=1-3^{-1.25}$

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

$2^{0.75}=1-3^{0.75}$

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

$2^{1.25}=1-3^{1.25}$

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

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3 years ago

PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

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Jobisdone [24]

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Ans

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3 years ago