Answer:
the slope-intercept equation of a line that passes through the coordinate (-4,5) and (8,-1) is
![y = - 0.5x + 3](https://tex.z-dn.net/?f=y%20%20%3D%20%20-%200.5x%20%2B%203)
Step-by-step explanation:
1) Apply the slope formula; y^2 - y^1 divided by x^2 - x^1
y^2 is -1
y^1 is 5
x^2 is 8
x^1 is -4
-1 - 5 = -6
8 - (-4) = 12
-6/12 is -1/2 or -0.5
2) To find the y-intercept, hoose either of the coordinates and replace y, m, and x in the y= mx+b formula.
5= -0.5(-4) + b
5= 2 + b
3= b
Answer: 40.9
Step-by-step explanation:
I got this by adding all the numbers up because that’s what you do you add up all the sides for perimeter
Answer:
C
Step-by-step explanation:
Once
![\sqrt{xy} = 6](https://tex.z-dn.net/?f=%5Csqrt%7Bxy%7D%20%3D%206)
We know that ![xy = 36](https://tex.z-dn.net/?f=xy%20%3D%2036)
There are infinity values for
, but considering ![x, y \in \mathbb{Z}](https://tex.z-dn.net/?f=x%2C%20y%20%5Cin%20%5Cmathbb%7BZ%7D)
Below we have all the solutions for ![x, y](https://tex.z-dn.net/?f=x%2C%20y)
Negative:
![\\x = -36 \text{ and } y = -1\\x = -18 \text{ and } y = -2\\x = -12 \text{ and } y = -3\\x = -9 \text{ and } y = -4\\x = -6 \text{ and } y = -6\\x = -4 \text{ and } y = -9\\x = -3 \text{ and } y = -12\\x = -2 \text{ and } y = -18\\x = -1 \text{ and } y = -36\\](https://tex.z-dn.net/?f=%5C%5Cx%20%3D%20-36%20%5Ctext%7B%20and%20%7D%20y%20%3D%20-1%5C%5Cx%20%3D%20-18%20%5Ctext%7B%20and%20%7D%20y%20%3D%20-2%5C%5Cx%20%3D%20-12%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-3%5C%5Cx%20%3D%20-9%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-4%5C%5Cx%20%3D%20-6%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-6%5C%5Cx%20%3D%20-4%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-9%5C%5Cx%20%3D%20-3%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-12%5C%5Cx%20%3D%20-2%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-18%5C%5Cx%20%3D%20-1%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%20-36%5C%5C)
Positives:
![x = 36 \text{ and } y = 1\\x = 18 \text{ and } y = 2\\x = 12 \text{ and } y = 3\\x = 9 \text{ and } y = 4\\x = 6 \text{ and } y = 6\\x = 4 \text{ and } y = 9\\x = 3 \text{ and } y = 12\\x = 2 \text{ and } y = 18\\x = 1 \text{ and } y = 36\\](https://tex.z-dn.net/?f=x%20%3D%2036%20%5Ctext%7B%20and%20%7D%20y%20%3D%201%5C%5Cx%20%3D%2018%20%5Ctext%7B%20and%20%7D%20y%20%3D%202%5C%5Cx%20%3D%2012%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%203%5C%5Cx%20%3D%209%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%204%5C%5Cx%20%3D%206%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%206%5C%5Cx%20%3D%204%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%209%5C%5Cx%20%3D%203%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%2012%5C%5Cx%20%3D%202%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%2018%5C%5Cx%20%3D%201%20%5Ctext%7B%20and%20%7D%20%20y%20%3D%2036%5C%5C)
We can see that ![x + y \neq 18](https://tex.z-dn.net/?f=x%20%2B%20y%20%5Cneq%2018)
Answer:
Step-by-step explanation:
x²+6x = 18
coefficient of the x term: 6
divide it in half: 3
square it: 3²
add 3² to both sides to complete the square and keep the equation balanced:
x²+6x+3² = 18+3²
(x+3)² = 27
x+3 = ±√27 = ±3√3
x = -3±3√3
![\large \mathfrak{Solution : }](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cmathfrak%7BSolution%20%3A%20%7D)
let's plug in the value of y :