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TiliK225 [7]
3 years ago
10

What shape is produced when slicing a right rectangular pyramid perpendicular to the base?

Mathematics
2 answers:
Mice21 [21]3 years ago
4 0

I believe the answer is B. Triangle

vfiekz [6]3 years ago
4 0

the answer is B. triangle

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find the ratio which are the points p(X,2) divides the line segment joining the point a(12,5) and b(4,-3) also find X plz give a
chubhunter [2.5K]

Answer:     ratio a:b = 3:5        p(X, 2) = p(9, 2)

<u>Step-by-step explanation:</u>

Plot points a = (12, 5) and b = (4, -3) and draw a line segment from a to b.

Notice that when y = 2, X = 9 so point p = (9, 2)      <em>see graph</em>

The distance from a to p = 3√2

The distance from b to p = 5√2

So the ratio of a:b = 3√2:5√2       = 3:5  <em>when simplified</em>

<em />

<em>To find the distance, use the distance formula OR pythagorean theorem.</em>

7 0
3 years ago
What value of x would make lines l and m parallel
g100num [7]

Answer:wdym

Step-by-step explanation:

7 0
3 years ago
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*Will mark brainest!!* Write an equation in point slope form <br> (-9,7) m=4
pshichka [43]

Answer:

y-7 = 4(x+9)

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is the point

y-7 = 4(x--9)

y-7 = 4(x+9)

4 0
3 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
Can someone please answer this question please answer it correctly please show work please help me I need it
Lena [83]

Answer:

B) Step 2

Step-by-step explanation:

Raul thought that 5 - 7 was 2, but it is actually -2.

If this answer is correct, please make me Brainliest!

5 0
3 years ago
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