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larisa [96]
3 years ago
12

The perimeter of a rectangle is 42 m. the length of the rectangle is 3 m less than twice the width. Find the length and width of

the rectangle
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0
Area Of Rectangle
= 
2 length × 2 width
= 2 l + 2 w

l = 2 w -3................equation (i)
2 l + 2 w = 42..........equation (ii)

2(2 w -3) + 2 w =42
4 w - 6 + 2 w = 42
4 w + 2 w = 42 + 6
6 w = 48
w =8

l = 2 w - 3
l = 2×8 - 3
l = 13

Length = 13
Width = 8

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lori has run 2.62 miles

Step-by-step explanation:

Do 26.2/10

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Reggy is a reading a 340 page book. It takes him 7 days to read the first 119 pages. At this rate, how much longer will it take
julsineya [31]

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5 0
3 years ago
Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465
disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is 3^{(x+2)}=15

We have to solve the above expression using change of base formula which is given as

\log _{b} a=\frac{\log a}{\log b}

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, x+2=\log _{3} 15

By using change of base formula,

x+2=\frac{\log _{10} 15}{\log _{10} 3}

x + 2 = 2.4649

x = 2.4649 – 2  = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

3 0
3 years ago
Read 2 more answers
What is the square root of 95.54
vladimir2022 [97]
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...

They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..

A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:

x-(f(x)/(df/dx))

In a square root problem you wish to know:

x=√n  where x is the root and n is the number

x^2=n

x^2-n=0

So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:

x-((x^2-n)/(2x)) which simplifies further to:

(2x^2-x^2+n)/(2x)

(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)

In this case the number, n=95.54, so a decent starting value for x would be 10.

Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.

10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397

The calculator result for my calc is: 9.7744565066299210578124802523381

So you see how accurate the newton method is in just a few iterations. :P


5 0
3 years ago
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