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Korvikt [17]
3 years ago
5

Suppose that the functions s and t are defined for all real numbers: s(x)=4x^2 t(x)=x^3 Write the expressions for (t+s)(x) and (

t*s)(x)evaluate for (t-s)(-1)

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0
A) (t+s)(x) = t(x) + s(x) = x^3 +4x^2

b) (t*s)(x) = t(x)*s(x) = (x^3)*(4x^2) = 4x^5

c) (t-s)(-1) = t(-1) - s(-1) = (-1)^3 - 4(-1)^2 = -1 -4 = -5
BigorU [14]3 years ago
3 0
Hey there !

Check the attachment.
Hope it helps you :)

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X² <span>+ 11x + 7

because 7 is a prime number, this doesn't factor prettily. you'll want to use the quadratic formula; if you aren't familiar with it, i'd either research it or look it up in your textbook, because it's clunky and not easily understood in this format:

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in your equation x² + 11x + 7 ... a = 1, b = 11, and c = 7. what you do is you take the coefficients of every term, then plug it into your equation:
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not pretty, i know. but, regardless, you can simplify it:
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and you can't simplify it further. -11 isn't divisible by 2, and 93 doesn't have a perfect square that you can take out from beneath the radical. the ± plus/minus symbol indicates that you have 2 answers, so you can write them out separately:

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they look confusing, but those are your two factors. they can be simplified just slightly by changing the signs in the middle due to the -11:

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and how these would read, just in case the formatting is too confusing for you: x plus the fraction 11 + root 93 divided by 2. the 11s and root 93s are your numerator, 2s are your denominator.
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