Answer:
2
Step-by-step explanation:
You count terms that are seperated by - and + signs. Any type of fraction is considered one term.
So you count 8y as one term and the rest is a whole fraction so you also count that as one term.
You add all the terms together and you have 2 terms in this equation.
Hope this helped :)
Answer:
a = -3
General Formulas and Concepts:
<u>Algebra I</u>
- Solving Exponential Equations
- Exponential Property [Rewrite]:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Solve for </u><em><u>a</u></em>
- Rewrite:
- Rewrite [Exponential Property - Rewrite]:
- Set:
Answer:
Domain: {-2,0,-1,4}
Range: {4,2,3,-2}
Step-by-step explanation:
1. Given the The relation Q={ (-2, 4), (0, 2), (-1, 3), (4, -2)}, you can determine the domain and the range as following:
DOMAIN:
The domain is the x-coordinate of each ordered pair. Therefore, you have:
Domain: {-2,0,-1,4}
RANGE:
The range is the y-coordinate of each ordered pair. Therefore, you have:
Range: {4,2,3,-2}
We Know that
For a function to have an inverse function, it must be one-to-one—that
is, it must pass the Horizontal Line Test.
1. On the interval [–pi/2, pi/2], the function
y = sin x is
increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full
range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is
one-to-one
sin x has an inverse function
on this interval [–pi/2, pi/2]
On the restricted domain [–pi/2, pi/2] y = sin x has a
unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x in the domain [–pi/2, pi/2] is [-1,1]
the range of y=sin-1 x in the domain [-1,1] is [–pi/2, pi/2]
1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]
On the restricted domain [0, pi] y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x in the domain [0, pi] is [-1,1]
the range of y=cos-1 x in the domain [-1,1] is [0, pi]
the answer is
<span>the values of the range are different because the domain in which the inverse function exists are different</span>
Answer:
Yes
Step-by-step explanation:
The angles are identical, so they are congruent.
Hope I helped! Plz leave a comment and a rating!
