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Lelu [443]
3 years ago
14

The function f(t)=16t2 represents the distance (in feet) a dropped object falls in t seconds. The function g(t)=s0 represents th

e initial height (in feet) of the object. A coin purse is dropped from a height of 144 feet. After how many seconds does the coin purse hit the ground?
Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

After 3 sec the object touches the ground

Step-by-step explanation:

The initial height of the object is s_0 = 144\ feet

The function that represents the distance of the object as a function of time is:

f (t) = 144-16t ^ 2

So, when the object touches the ground we have to:

f (t) = 0

So:

0 = 144 - 16t ^ 2

16t ^ 2 = 144

f (t) = g (t)

We solve the equation for t:

t ^ 2 = \frac{144}{16}

t ^ 2 = 9

t = +3    and     t = -3

We take the positive solution.

t = 3\ sec.

After 3 sec the object touches the ground

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Z = ma for a please help
il63 [147K]

Answer:

Z = Ma = ba

You made a typo. One of those = signs should either  

be a + and a -.  Here are all possibilities:

1.     Z+Ma = ba, solve for a

     Ma-Ba = -Z

    a(M-B) = -Z

         a = -Z/(M-B)

2.        Z = Ma+ba, solve for a

     Ma+ba = Z

    a(M+b) = Z

         a = Z/(M+b)  

3.     Z-Ma = ba, solve for a

         Z = Ma+ba

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         a = Z/(M+b)

4.       Z = Ma-ba, solve for a

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Step-by-step explanation:

3 0
3 years ago
Use the image below to answer questions 8-9
Dovator [93]

Answer:

Angle 1=42.5

Angle 2=95

8 0
2 years ago
What is the length of BC in the right triangle below
Anna [14]

Answer:

<h2><em>1</em><em>5</em><em> </em><em>units</em></h2>

<em>The </em><em>length </em><em>of </em><em>BC </em><em>is </em><em>1</em><em>5</em><em> </em><em>units.</em>

<em>Solution,</em>

<em>Hypotenuse(</em><em>h)</em><em>=</em><em>?</em>

<em>perpendicular(</em><em>p)</em><em>=</em><em>1</em><em>2</em>

<em>base(</em><em>b)</em><em>=</em><em>9</em>

<em>Using </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>

<em>{h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {h}^{2}  =  {12}^{2}  +  {9}^{2}  \\ or \:  {h}^{2}  = 12  \times 12 + 9  \times 9 \\ or \:  {h}^{2}  = 144 + 81 \\ or \:  {h}^{2}  = 225 \\ or \: h =  \sqrt{225}  \\ or \: h =  \sqrt{ {15}^{2} }  \\ h = 15</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

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6 0
3 years ago
Read 2 more answers
Please answer this as soon as possible
skelet666 [1.2K]

Answer:x=-8

Step-by-step explanation:

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3 0
3 years ago
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Don't know what to do :\\
____ [38]
Answer: Choice A) 12x^2 - 48x + 21; all real numbers

===========================================================

Work Shown:

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(f * g)(x) = ( f(x) ) * ( g(x) )
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The domain is the set of all real numbers because we can plug in any number in for x, to get some output for y. There are no issues to worry about such as division by zero errors, square root of a negative number, etc. 
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