Answer:
X= 18; Y=15
Step-by-step explanation:
As a student myself working this out I cannot explain how I got the answer but I know it is correct.
Answer:
1.33×10^-6
Step-by-step explanation:
5.32 x 10^-7= 5.32×10^(-5-2)= 5.32×10^-2×10^(-5)
=0.0532×10^-5
(0.0532×10^-5) (2.5 x 10^-5)
0.0532×2.5 × 10^-5
0.133×10^-5= 1.33×10^-1 ×10^-5
1.33×10^-6
Answer:
D. No, because group A is already the control group.
Answer:
m(arc ZWY) = 305°
Step-by-step explanation:
8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,
Angle formed by two tangents = 
= 
= 
= 40°
9). Following the same rule as above,
Angle formed between two tangents = 
125 = ![\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%7D%29-m%28%5Ctext%7Bminor%20arc%7D%29%5D)
250 = ![[m(\text{arc ZWY})-m(\text{arc ZY})]](https://tex.z-dn.net/?f=%5Bm%28%5Ctext%7Barc%20ZWY%7D%29-m%28%5Ctext%7Barc%20ZY%7D%29%5D)
250 = m(arc ZWY) - 55
m(arc ZWY) = 305°
Therefore, measure of arc ZWY = 305° will be the answer.
10). m(arc BAC) = ![\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Bm%28%5Ctext%7Barc%20BDC%7D%29-m%28%5Ctext%7Barc%20BC%7D%29%5D%29)
= 
= 
= 74°