9(2k+3)+2=11 (k-y)
k=-11/7 y+ -29/7
The first, fourth and fifth ones are linear.
The second, third and sixth are all nonlinear.
You can tell this by the fact that their lead exponents are not 1.
Answer:
0, 5/4
Step-by-step explanation:
If
, you get 0=0, which is obviously true.
As long as K is not 0, you can divide by k and get
which is solved by 