Answer: Graph the solution to the following system of inequalities: x>/ 0 y<2 x+ 3y > 0
Step-by-step explanation:
Explanation:
Find the two closest square numbers to 1659.
40*40=1600
41*41=1681
Decide much closer to either 1600 or 1681 is 1659.
If it is exactly halfway between the two numbers, the square root is 40.5.
If it is closer to 1600, the sq rt decimal is between 1 and 4.
If it is closer to 1681, the sq rt decimal is between 6 and 9.
The diagram is attached below
Beaker 1: The measurement line is between 32 and 33. There are 5 lines between 32 and 33. Making line is between third line and fourth line(between 6 and 8). So 32.7
Beaker 2: The measurement line is between 30 and 40. We can clearly see the measurement line at 32. So its 32
Beaker 3: The measurement line is between 32.7 and 32.8. We have 10 small lines inbetween them. Measurement line at 4. So its 32.74
(b) the amount of water in each of 3 beakers are not same because we can measure the difference. But they are close to each other.
Answer:
m<ACB = 107*
Step-by-step explanation:
First we have to find the angle of m<CEB.
We know that the value of that angle plus m<CEP equals a total of 180, so we subtract the value that we have (147*) from 180 and we get 33*.
33* Is also the value of m<CAB.
33+40 = 43. 180-43 = 107.
I just figured it out so I’ll answer it on this account lol.
Q1 = 32, Q2 = 45, Q3 = 52
Interquartile range = 52 - 32 = 20
Range = 68 - 21 = 47