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3 years ago

How to write this in slope-intercept form? 8x + 10y = 40

Mathematics

2 answers:

worty [1.4K]3 years ago

4 0

Answer:y=-4/5x+4

Step-by-step explanation:

saveliy_v [14]3 years ago

4 0

Answer:

y = -4/5 + 4

Step-by-step explanation:

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What is 7.125 simplified as a fraction?

Luba_88 [7]

Answer: 7 $\frac{1}{8}$ or $\frac{57}{8}$

Step-by-step explanation:

0.125 = 1/8

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2 years ago

A child throws a ball up in the air to a height of 3.5 m and catches it at the same point from which he threw it. The ball is in

dimaraw [331]

$S = 3,5 + 3,5 = 7 m \\ V = \frac{\triangle S}{\triangle T} = \frac{7}{1,7} \approx 4,12 \frac{m}{s}$

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3 years ago

Kylie and chen have 69 stickers. Kylie and Olivia have 95 stickers. The ratio of the number of stickers Olivia has to the number

White raven [17]

Kylie has 30 stickers

7 0

3 years ago

Which expression is equivalent 1/4 (4/7x - 1/2) - 3/8

Rainbow [258]

Answer:

Step-by-step explanation

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5 0

2 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago