Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
Answer:
One way to identify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles.
Step-by-step explanation:
so if I was you I would use that strategy to try to find the pair of the Alternate exterior angles.
so the agles are probably 1 and 7 but i don’t want you to get it wrong so here’s a picture Of an example.
Answer:
26.5
Step-by-step explanation:
used calculator
Answer:
AAS Congruence Theorem
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
