All categories

2 years ago

Cost of a sled:$99.50 the markup is 95% what is the answer

Mathematics

1 answer:

Bezzdna [24]2 years ago

5 0

$99.50 * 0.95 = $94.53
$99.50 - $94.53 = $4.97

You might be interested in

How can you the unit rate on a graph that goes through the origin ?

Nonamiya [84]

It must be about the origin in order to do that

5 0

3 years ago

Let f(x) = 2x - 3. If f(x) = 15, what is x?

iragen [17]

Answer:

9=x

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please help anyone and thank you

snow_lady [41]

Answer and Step-by-step explanation:

The two statements that are true are statement 1 and statement 4:

- The sum of pi and 0 is irrational.

- The product of $\frac{9}{5}$ and $\sqrt{19 }$ is irrational.

Pi is an irrational number, and the square root of 19 is irrational. That's because these numbers can't be put into a simplified fraction to encompass all the digits it contains.

#teamtrees #PAW (Plant And Water)

8 0

2 years ago

The ratio of blue tacks to red tacks on the bulletin board is 3 to 5. there are 50 red tacks. how many blue tacks are on the boa

natulia [17]

3:5=x:50

Therefore 5 ×x = 50

x = 10

Therefore 3 × 10 = 30

therefore 30 blue pens

proof = 30 blue + 50 red= 3+ 5

therefore 80 = 8x

8 0

3 years ago

Read 2 more answers

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by $\dfrac{2}{3}$ .

8 0

3 years ago