I say <span>A solid can diffuse into both a liquid and another solid. </span>
Explanation:
The given reaction at cathode will be as follows.
At cathode:
,
= -0.761 V
At anode:
,
= 0.761
Therefore, net reaction equation will be as follows.

Initial: 0.129 - - 0.427
Change: -0.047 - - -0.047
Equilibrium: (0.129 - 0.047) (0.427 - 0.047)
= 0.082 = 0.38
As
for the given reaction is zero.
Hence, equation for calculating new cell potential will be as follows.
E_{cell} = ![E^{o}_{cell} - \frac{RT}{nF} ln \frac{[Zn^{2+}]_{products}}{[Zn^{2+}]_{reactants}}](https://tex.z-dn.net/?f=E%5E%7Bo%7D_%7Bcell%7D%20-%20%5Cfrac%7BRT%7D%7BnF%7D%20ln%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D_%7Bproducts%7D%7D%7B%5BZn%5E%7B2%2B%7D%5D_%7Breactants%7D%7D)
= 
= 0.019
Thus, we can conclude that the cell potential of the given cell is 0.019.
Answer:
<h2>The answer is 1.5 L</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is

Since we are finding the new volume

From the question we have

We have the final answer as
<h3>1.5 L</h3>
Hope this helps you
Answer:
Na₂CO₃ · 10H₂O
Explanation:
The formula for sodium carbonate hydrate is:
Na₂CO₃ · xH₂O
The unknown "x" is the number of water molecules contained in the hydrate.
To find "x" we have to use the hydrogen percentage in the sample, 7.05 % H.
First we calculate the molecular weight of Na₂CO₃ · xH₂O:
molecular weight of Na₂CO₃ · xH₂O = 23 × 2 + 12 + 16 × 3 + 18x
molecular weight of Na₂CO₃ · xH₂O = 106 + 18x g/mole
Now we devise the fallowing reasoning tanking in account 1 mole of Na₂CO₃ · xH₂O:
if in 106 + 18x grams of Na₂CO₃ · xH₂O we have 2x grams of hydrogen
then in 100 grams of Na₂CO₃ · xH₂O we have 7.05 grams of hydrogen
106 + 18x = (100 × 2x) / 7.05
106 + 18x = 28.4x
106 = 28.4x - 18x
106 = 10.4x
x = 106 / 10.4
x = 10.2 ≈ 10
The formula for the washing soda is Na₂CO₃ · 10H₂O.