A. Silver
Proton- 47
Electrons- 47
Neutron- 61
108-47=61
Answer:
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Answer:
Concentration of the sugar in the solution increases
Answer:
The product will be propanoic acid .
Explanation:
Under the action of strong oxidizing agent that is potassium dichromate in an acidic medium primary oxidizes the primary alcohols into carboxylic acid .

So, when propanol is treated with potassium dichromate in an acidic medium it get converted into propanoic acid.

B. More n2and I wwould form