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Svet_ta [14]
3 years ago
15

What is the purpose of a unit conversion?

Chemistry
1 answer:
Nataly [62]3 years ago
8 0

<em><u>Unit conversion is very important because the rest of the world other than three contries uses the metric system. So, converting unitsis important in science because it uses the metric system. The metric system aremeasurements like cm, m, l, mL, etc.</u></em>

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Balance the following reaction. As2S3 + 9O2 → 2As2O3 + SO2
kumpel [21]

Answer:

2As2S3 + 9O2 = 2As2O3 + 6SO2

Explanation:

8 0
3 years ago
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A student jumps of a sled toward the west after it stops at the bottom of an icy hill. Based on the law of action-reaction, in w
Delicious77 [7]

Answer:

East

Explanation:

Given Newton's third law of motion; "Action and reaction are equal and opposite", when a student jumps off a sled toward the west after it stops at the bottom of an icy hill, the sled will move in the East direction.

This is because, the force exerted on the sled is a reaction force and is opposite in direction to the force that thrusts the boy westward though equal in magnitude with the former.

3 0
2 years ago
How can we tell when something is polar or non-polar in an Inter-molecular Force?
Montano1993 [528]
If the substance mixes with water it's polar. If it doesn't it ms non polar.
7 0
3 years ago
Sulphur +_________ gives ➙ sulphur oxide
Luba_88 [7]

Answer:

Sulphur + oxygen gives ➙ Sulphur oxide

Explanation:

Sulfur oxide is a compound that consists of sulfur and oxygen molecules. I hope this helps!

3 0
3 years ago
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Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

Explanation:

The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
2 years ago
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