Since both have same speed
v(rel.) x-(-x)= 10( from law of vector addition)
2x=10,x= 5m/sec
I think it’s k and i am sorry if i am wrong but yeah…
The measure of the ∠Q = 41°
By law of cosines:
a law in trigonometry: the square of a side of a plane triangle equals the sum of the squares of the remaining sides minus twice the product of those sides and the cosine of the angle between them.
Which can we stated as:

solving equation using normal algebra:
60cos(Q) = 36 + 25 - 16
60 cos(Q) = 45
cos(Q) = 45/60
cos(Q) = 3/4

Thus, Q = 41°
Hence, the measure of the smallest angle in a triangle whose sides have lengths 4, 5, and 6. ∠Q is 41°.
To learn more about Finding angles visit:
brainly.com/question/3067469
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Answer:
polynomial of degree 10
Step-by-step explanation:
The degree of the polynomial is the sum of the exponents, that is
y³ → has degree 7 + 3 = 10
Answer:
x=40
Step-by-step explanation:
In the picture, it seems that angles BHC, CHD, and DHE form a line, 180 degrees. So to solve, set up an equation:

Take off the parentheses and solve.
Subtract 5, 55 and 40 from both sides, or add them together, then subtract.
5+55+40=100
You get:

Divide both sides by 2
You get:
<h3>
![[x=40]](https://tex.z-dn.net/?f=%5Bx%3D40%5D)
</h3><h3>
</h3>
I hope this helps!