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3 years ago

Determine whether the system of equations has one solution, no solution, or infinitely many solutions. 4x=10+4y and 2x-2y=15

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

infinitely many solutions

Step-by-step explanation:

Given the simultaneous equation

4x=10+4y... 1

2x-2y=15 .... 2

_____________

4x-4y = 10 * 1

2x-2y = 15 * 2

__________--

4x-4y = 10

4x-4y = 30

Add both equation

8x - 8y = 10+30

8x-8y = 40

Divide though by 8

x-y = 5

x = 5 + y

Since the result gave 1 equation and 2 unknowns, then we will let x =k

k = 5 + y

y = k -5

k can be any integer

(x,y) = (k, k-5)

This show that the equation has infinitely many solutions

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3 years ago

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Step-by-step explanation:

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3 years ago

Which expression is equivalent to 14 x 14?

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Step-by-step explanation:

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4 years ago

Karen earns $54.60 for working 6 hours. If the amount she earns varies directly with the

Andrei [34K]

Given:

Karen earns $54.60 for working 6 hours.

Amount she earns varies directly with the number of hours she works.

She need to work to earn an additional $260.

To find:

Number of hours she need to work to earn an additional $260.

Solution:

Let the amount of earnings be A and number of hours be t.

According to question,

$A\propto t$

$A=kt$ ...(i)

where, k is constant of proportionality.

Karen earns $54.60 for working 6 hours.

$54.60=k(6)$

Divide both sides by 6.

$\dfrac{54.60}{6}=k$

$9.1=k$

Put k=9.1 in (i).

$A=9.1t$

Substitute A=260 in the above equation.

$260=9.1t$

Divide both sides by 9.1.

$\dfrac{260}{9.1}=t$

$28.5714=t$

$t\approx 29$

Therefore, she need to work extra about 29 hours to earn an additional $260.

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