Determine whether the system of equations has one solution, no solution, or infinitely many solutions. 4x=10+4y and 2x-2y=15
1 answer:
Answer:
infinitely many solutions
Step-by-step explanation:
Given the simultaneous equation
4x=10+4y... 1
2x-2y=15 .... 2
_____________
4x-4y = 10 * 1
2x-2y = 15 * 2
__________--
4x-4y = 10
4x-4y = 30
Add both equation
8x - 8y = 10+30
8x-8y = 40
Divide though by 8
x-y = 5
x = 5 + y
Since the result gave 1 equation and 2 unknowns, then we will let x =k
k = 5 + y
y = k -5
k can be any integer
(x,y) = (k, k-5)
This show that the equation has infinitely many solutions
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Step-by-step explanation:
Wai 1unit+45
Cheryl 1unit
Zheng 4units+180
Altogether 6units+225=510
6units = 510-225
6units=285
1unit=285÷6
= $47.5
So Wai =47.5+45 = 92.5
Cheryl =47.5
Zheng =4×47.5+180 =370
370-47.5=$322.5
Answer $322.5
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Answer:
Step-by-step explanation:
Answer E is the only one that is close