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3 years ago

What is the average of 3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4

Mathematics

1 answer:

melisa1 [442]3 years ago

4 0

Answer:

1 3/8

Step-by-step explanation:

Well to find the average or the mean we need to add all the numbers,

3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4

= 11

Then we divide t by the number of numbers in the set.

11 ÷ 8 = 1 3/8

Thus,

the average in the set is 1 3/8.

Hope this helps :)

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Anna71 [15]

Answer:

The value of RA is " 9.43".

Step-by-step explanation:

In the given question there is some typing mistake so, the points are:

R =(2, 5)

A= (-3, -3)

Find:

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Formula:

$D= \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2} \\\\\ compare \ the \ value \\\\x_1 = 2\\y_1=5\\x_2=-3\\y_2= -3$

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0.00065 in Standard form

umka2103 [35]

Try 6.5x10^4
Pretty sure that’s it, If not I’m sorry!

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3 years ago

Read 2 more answers

Suppose u1, u2, ..., un are independent random variables and for every i = 1, ..., n, ui has a uniform distribution over [0, 1].

sattari [20]

$Z=U_{(1)}=\min\{U_1,\ldots,U_n\}$

has CDF

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$F_{U_i}(u_i)=\begin{cases}0&\text{for }u_i$

and so

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Differentiate the CDF with respect to $z$ to obtain the PDF:

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3 years ago

A test preparation claims that more than 50% of the students who take their test prep course improve their scores by at least 1

satela [25.4K]

Answer:

Step-by-step explanation:

Corresponding scores before and after taking the course form matched pairs.

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μd = scores before taking the course minus scores before taking the course.

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H0: μd ≥ 0

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H1: μd < 0

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