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neonofarm [45]
3 years ago
13

Turn 5 5/16 as a decimal

Mathematics
2 answers:
bulgar [2K]3 years ago
5 0
4.16 is your answer
Alecsey [184]3 years ago
5 0
Wait isn't it 5.3125 because if 5 is the whole number then that would stay the same as 5.0 while you need to solve what 5÷16 is and that equals to 0.3125 if it is asking for what 5 and 5/16 are as a decimal it's going to be 5.3125

Easier way to put it 16/16 is 1 and there are five of these. So do 16 x 5 =80 and add that with 5 to equal 85 then divide that by 16 and you get 5.3125
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Step-by-step explanation: If you look closely, putting a 100 wouldn't make sense

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The object on the right is made from a square-based pyramid joined to a cuboid.
spayn [35]

Answer:

Density of steel = 80.73 gm/cm^3

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

V_{Cuboid} = l \times w \times h

V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3

Density of Wood , D_{Cuboid}= 0.68g/cm^3

We know that formula of Density is:

Density = \dfrac{Weight}{Volume}

D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}

Putting the values:

W_{Cuboid} = 324 \times 0.68 = 220.32\ gm

Total weight = W_{Cuboid} + W_{Pyramid}

970 = 220.32 + W_{Pyramid}

W_{Pyramid} = 749.68 gm

Volume of pyramid is given as:

V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}

Base is a square with side 6 cm

V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3

Density of Steel/Pyramid:

D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3

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3 years ago
F(x)= x/x-7<br> What is the domain of f?
Dmitry [639]

Answer:

(-∞,7) U (7,∞)

Step-by-step explanation:

All real values of x such x ≠ 7

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3 years ago
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Answer:

-c-4≥8

Step-by-step explanation:

Just ask!

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P1=(-1,3) and P2=(5,-1) <br><br> Find the distance from p1 to P2
LenaWriter [7]

Answer:

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

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d = sqrt(36 + 16)

d = sqrt(52)

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2 years ago
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