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My name is Ann [436]
3 years ago
15

Write 2 expressions that are equivalent to the given expression 4(m+3+5m)

Mathematics
2 answers:
Marrrta [24]3 years ago
6 0
Add m
4(3+6m)
12+24m
1/2=m
DaniilM [7]3 years ago
3 0
OK you can switch the 3 and 5 around and another is you can switch the 4 and 3.

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(2.4 x 10^2) (6.1 x 10^5
frosja888 [35]
The answer is 1.464 x 10^8
3 0
2 years ago
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I tried to solve this problem and can’t can you tell me the answer
Kitty [74]
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6 0
3 years ago
Use synthetic division to evaluate f(x) = –2x^3+ 3x – 6 when x = -5.
fgiga [73]

Answer:

-131

Step-by-step explanation:

Use -5 in place of x

f(x) = –2x^3+ 3x – 6

f(x) = -2*-5^3+3*5-6

6 0
3 years ago
William and Stephanie are playing a rather dangerous game of catch on the rooftops of skyscrapers in downtown Chicago. William i
olasank [31]
The question involves the concept & equations associated with projectile motion.

Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²


Of the possible equations of motion, the one we'll find useful is:

y₂ = y₁ + v₁t + 1/2gt²

We can just plug and chug to define the equation of motion:

<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>


<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>

7 0
4 years ago
True or false is a relation in which each y value has only 1 x value
boyakko [2]

Answer:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

Step-by-step explanation:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

The reason is very clear that we can not have the repeated x-values (two same x-values).

For example, given the set of the ordered pairs of a relation

{(3, a), (6, b), (6, c)}

As the same x values (x=6) has two different Y values. Hence, the stated relation is not a function.

In order to be a function, a relation must have only 1 x-value for each y-value.

Therefore, the statement is true that a function is a relation in which each y value has ONLY 1 x value.

5 0
3 years ago
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