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muminat
3 years ago
6

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

Answer:  

The slope of a line that is perpendicular to the given line is -\frac{3}{2}

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

Solve for "y" from the equation of the line 2x - 3y - 5 = 0:

2x - 3y - 5 = 0\\\\-3y=-2x+5\\\\y=\frac{-2}{-3}x+\frac{5}{-3}\\\\y=\frac{2}{3}x-\frac{5}{3}

You can observe that the slope of this line is:

m=\frac{2}{3}

By definition, the slopes of perpendicular lines are negative reciprocal, then, the slope of a line that is perpendicular to the give line, is

m=-\frac{3}{2}

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Answer:

Step-by-step explanation:

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In ΔEFG, the measure of ∠G=90°, the measure of ∠E=20°, and GE = 75 feet. Find the length of EF to the nearest tenth of a foot.
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Step-by-step explanation:

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3 years ago
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Alex_Xolod [135]
15.04 degrees or answer A is correct.


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You can transform the law of sines formulas to solve some problems of triangulation (solving a triangle). You can use them to find:

The remaining sides of a triangle, knowing two angles and one side.
The third side of a triangle, knowing two sides and one of the non-enclosed angles. In some cases (ambiguous cases) there may be two solutions to the same triangle. If the following conditions are fulfilled, your triangle may be an ambiguous case:
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Angle α is acute (α < 90°);
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