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3 years ago

9

The figure below is a diagram of a trapezoidal table that needs to be stained. Each can of stain will cover 50 square inches.

1 answer:

Agata [3.3K]3 years ago

4 0

To find the number of cans needed, divide the total area by the area 1 can will cover:

350 / 50 = 7 cans are needed.

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The area of a rectangle is 525 sq cm. the ratio of the length to the width is 7:3. find the length and width.

nalin [4]

Suppose the length is 7x, the width is then 3x
7x*3x=525
21x²=525
x²=25
x=5
so the length is 7*5=35, and the width is 3*5=15

3 0

3 years ago

Keisha wants to meet for 90 minutes so far she has read 30% of her goal how much longer does she need to read to reach her goal

sladkih [1.3K]

Answer:

30% of 90

30% x 90

30/100 =3/10

3/10 x 90 = 270/10

270 = 27

90 - 27 = 63

Keisha has to read 63 more minutes to reach her goal.

4 0

3 years ago

What is t if 3/5=2/3t.

Dvinal [7]

<span><span>т = <span><span>9/10

Я сподіваюсь допомогла ^ - ^
</span></span></span><span>
</span></span>

6 0

3 years ago

A computer tablet is 0.24 meter long. How long is the computer tablet in centimeters? Please show work

AysviL [449]

Answer:

1 meter equals 100 centimeters, to find out how many centimeters you want to take 0.24*100= 2.4,

Therefore; the computer tablet is 24 centimeters long.

8 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

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