Answer:
see below
Step-by-step explanation:
Put -1 where x is in each expression and evaluate it.
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You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...
(x +1)
Substituting x=-1 into this factor makes it be ...
(-1 +1) = 0
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Evaluating the first expression, we have ...

This first expression is one you want to "check."
You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)
Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station
Answer:
about 3/4
Step-by-step explanation:
To tell what the y value of a certain x value will be is very simple if we have a graph--you can just look at the portion of the graph where x = 6. At that point, it appears to be 3/4 ish on the y-axis
A^2+b^2=c^2
a^2+9^2=15^2
a^2+81=225
-81 -81
a^2= 144 (square root both sides)
a=12
Answer:
20
Step-by-step explanation:
Once you give 1 candy to each of the 4 kids, you will have 3 remaining. The number of ways those can be distributed to 4 kids is given by ...
(n+k-1)C(n)
where n is the number of candies, and k is the number of kids. "aCb" is the number of ways a can be taken b at a time:
aCb = a!/(b!(a-b)!)
For n=3 and k=4, this is ...
(3+4-1)C(3) = 6C3 = 6!/(3!·3!) = 20
There are 20 ways to distribute 7 candies to 4 kids so that each kid receives at least one.