Question

Find the distance and midpoint between (- 8, 1) and (4, 6)

Answer 1

Answer:

Distance: 13, Midpoint: (-2, 3.5)

Step-by-step explanation:

The distance formula is $\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }$. We can plug in the numbers from your question so it would be √(4+8)^2+(6-1)^2 =  √144+25=169 =√169 = 13

The midpoint formula is ((x1+x2)/2, (y1+y2)/2), which is -8+4/2, 1+6/2 = (-2, 3.5).