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scoray [572]
3 years ago
5

European rabbits were introduced to Australia in 1859. The rabbits reproduced rapidly in their new environment, displaced other

animals and overgrazed vegetation. In an attempt to reduce the rabbit population, a deadly virus was introduced in 1951. When the virus was first introduced, the rabbits died in large numbers, but the death rate decreased over time. What statement best explains the decrease in the rabbit death rate? A) The virus had a short life span and died out with the rabbits. B) Natural selection favored rabbits that were resistant to the virus. C) The rabbits died of natural causes and the introduced virus did not work. D) Young rabbits exhibited a learned behavior and began to avoid being infected by the virus.
Biology
1 answer:
Goryan [66]3 years ago
6 0

Answer:

B) Natural selection favored rabbits that were resistant to the virus

Explanation:

Most likely, virus resistance occurred over time, as a consequence of mutation. Individuals that carried the resistance mutation become favourable by natural selection.

Natural selection is evolutionary mechanism which favours traits of an organism that help him survive and reproduce (increase organism's fitness). In the example above, resistant rabbits that survived had the favorable trait (resistance) by natural selection.

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Answer:

a. 0.7

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As the random mating population was escaped from external evolutionary forces such as mutation, natural selection, and migration, the gene frequency will not change over time. The population will be at Hardy-Weinberg equilibrium throughout the time.

<u>As the number of sleepyheads (recessive trait) was 90 out of class of 1000 students at the start of course.</u>

<u />

q²=0.09 ∵ fraction of sleepyheads = 90/1000 = 0.09 denoted by q²

q that is the recessive gene frequency will be equal to 0.3 (by taking square root of P²

Hence, <em>allele frequency of a allele is 0.3</em>

<em></em>

As, frequency of dominant allele A is denoted by letter p and p+q=1

∴ p=0.7 As p=1-0.3

Hence,<em> allele frequency of A allele is 0.7</em>

<em></em>

Counting the probability of aa alleles (sleepyheads);

As a= 0.3

∴ aa= 0.3×0.3 = 0.09 (In terms of percentage, it is 9%)

To 0.09×1000= 90 or 9% of 1000 = 90

Hence, 90 students should be sleepyheads.

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