A standard deck of 52 playing cards includes 13 of each of the 4 suits :
clubs , diamonds, hearts and spades.
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Of these, the clubs and spades are black, and the hearts and diamonds are red.
Each of the 4 suits contains a King, a Queen, and a Jack (The face cards).
The Sample Space is the set of all possible outcomes in an experiment. Thus, the sample space in our problem is the set containing each of the 52 cards.
The number of this set, is denoted by n(S), and it is equal to 52.
If E is a certain event, then P(E)=n(E)/n(S).
A) E: </span><span>an ace or heart, what is P(E)?
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The event E can occur if any of the 13 hearts is drawn, or if any of the clubs ace , diamonds ace, or spades ace is drawn.
Thus, n(E)=13+3=16. That is, P(E)=n(E)/n(S)=16/52=0.308
B) E: <span>an even number or a spade. P(E)=?
Event E can occur as follows:
Any spade is drawn, that is 13 cards. Or, any of the cards 2, 4, 6, 8, 10 of one of the </span>clubs , diamonds, or hearts is drawn.
Thus, n(E)=13+5*3=13+15=28.
This means that P(E)=n(E)/n(S)=28/52=0.538
C) E: <span>a red queen or black face card. P(E)=?
There are a total of 2*3=6 black face cards, and 2 red queens. This means that
n(E)=6+2=8.
Thus, P(E)=n(E)/n(S)=8/52=0.154</span>
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D) E: </span><span>a face card or a heart. P(E)=?
There are a total of 13 heart cards, and 3*3=9 non heart, face cards.
Thus, n(E)=13+9=22.
</span>This means that, P(E)=n(E)/n(S)=22/52=0.423
Answers:
A) 0.308
B) 0.538
C) 0.154
D) 0.423
Answer:
the approximate APY of the account is 2.73%
Step-by-step explanation:
We know the formula for APY which is given by
here, r= interset rate = 2.7% = 0.027
n = compounding cycles = 4
On plugging these values in the above formula, we get
On simplifying this we get
0.02727 = 0.02727*100
= 2.73%
Therefore, the approximate APY of the account is 2.73%
2500-700 = 1800
1800/5 = 360
The annual depreciation of the camera is $360.
Answer:
The value of the probability is 0.9811
Step-by-step explanation:
Given that the Probability (boy) = 0.516, and that the birth of a boy is mutually dependent on the birth of a girl, we can say that,
The Probability (girl) = 1 - Probability(boy).
The interpretation of the question, "at least one of them is a girl" is that:
Out of 6 births, there could be one, two, three, four, five or six (all) girls.
Finding this probability for each possibility, would be time taking. The mutually exclusive event to this is that "there will be no girls born at all"
so, we can find:
Probability (no girl at all in six births) = Probability (six boys out of six births)
= 0.516 ∧ 6 = 0.0189
Therefore,
Probability (at least one of them is a girl) = 1 - Probability (no girl at all in six births) = 1 - 0.0189 = 0.9811
5 + -4 is 1
This is because lets say you have 5 cookies, you have -4 cookies, in order for you to have the correct amount, you can’t have -4 cookies so you have to subtract those cookies from 5
So 5-4 is 1
14+ -13 is 1 as well
This is because of the same concept. You can’t have -13 cookies, therefore you have to subtract them!
Hopefully I helped you out, If i didn’t I’m so sorry
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