HELP HELP HELP FIRST RIGHT ANSWER GETS BRAINLIEST

Kendra is determining the distance between the points (6, 8) and (2, –3). Her work is shown below.

Sergeeva-Olga [200]

The x-coordinates need to be subtracted and the y-coordinates need to be subtracted.

The x-coordinates are 6 and 2.
Their subtraction is 6 - 2.
Kendra did this correctly.

The y-coordinates are 8 and -3.
Their subtraction is 8 - (-3) = 8 + 3 = 11.
Kendra did this incorrectly. She should have had 8 - (-3) = 8 + 3 = 11.
Then she'd square 11.
Instead, she subtracted 8 and -3 incorrectly and got 8 - 3 = 5.
Then she squared 5 when she should have squared 11.

5 0

3 years ago

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How many solutions?

MakcuM [25]

Answer:

0 solutions

Step-by-step explanation:

These system of equations are inconsistent (parallel to each other) which means that there are no solutions to this system.

7 0

3 years ago

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If <img src="https://tex.z-dn.net/?f=f%28x%29%3D3%5Ex" id="TexFormula1" title="f(x)=3^x" alt="f(x)=3^x" align="absmiddle" class=

SOVA2 [1]

$$f(x)+f(x+1) \stackrel{1}{=} 3^x+3^{x+1} \stackrel{2}{=} 3^x+3^x\cdot3^1\stackrel{3}{=}3^x+3\cdot3^x\stackrel{4}{=}4\cdot3^x\stackrel{5}{=}4\cdot f(x)$

1) Substitution from definition.

2) We use $$x^{a+b}=x^a\cdot x^b$

3) We are changing the order of 3 and $3^x$ .

4) We add 1 and 3 $3^x$ and we get $4\cdot 3^x$

5) Substitution from definition (but the other way than at the beginning).

8 0

3 years ago

Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar

xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ $_{e}^2$ → $S_{e} ^{2}$ ), you have to use the following formula: