We have to deal with the distance in more detail
If the turtle is 11 times faster than the snail, the amount of distance he will cover is 11 times more.
d/(360 - d) = 1/11
11d = 360 - d
12d = 360
d = 30 The Snail covers 30 meters. The turtle covers 11*30 = 330 meters.
Answers
Rate of snail = 30 meters / 40 minutes = 3/4 meter / minute
Rate of turtle = 330 meters / 40 minutes = 8.25 meters / minute.
Answer:
1/8 and 2/6 put them in common terms making it
3/24 and 8/24 so you add them giving you
11/24 which can't be simplified so she used 11/24 of a gallon of pain in total
Step-by-step explanation:
20/8 = 10/4 = 5/2
So, it's mixed form would be 2 1/2
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula for a geometric sequence.
The common ratio is 3, and 2 is the 1st term.
Thus, we have a1=2(3)^(n-1)
Hope this helps :)
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds